Leo
efe8e165cf
按 leo 鐵律（2026-06-14）把插件從「直接 SQL 操作基本盤表」改寫成 「只透過基本盤 arcrun/kbdb HTTP API 讀寫」。零建表、零 migration、零 SQL。 - 新增 src/lib/kbdb-client.ts：唯一對外通道，封裝 entries/templates/records API - 新增 src/lib/templates.ts：triplet/entity template 定義（替代建表） - 改寫 21 個違規 action（triplet/graph/entity/search）→ 走 client，圖在插件層記憶體組裝 - 移除所有 migrations、D1/Vectorize/AI 綁定；embedding/語意搜尋歸基本盤 optional 模組 - index.ts 只掛 triplets/graph/entities/search 路由；基本盤路由歸 arcrun/kbdb - 測試改走 mock client（純 node）；裁剪 CLAUDE.md 只留 graph 插件 + 鐵律 - 修正 SDD design.md「讀現狀推翻鐵律」的錯誤判斷（共用 D1 → API-as-Wall） Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
48 lines
1.6 KiB
TypeScript
48 lines
1.6 KiB
TypeScript
// graph 查詢 — 圖在插件層記憶體組裝（不靠 DB VIEW），走 mock client。
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import { describe, it, expect } from 'vitest';
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import { createTriplet } from '../src/actions/triplet-crud';
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import { listNodes, getNodeEdges, getNeighbors } from '../src/actions/graph-nodes';
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import { findShortestPath } from '../src/actions/graph-path';
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import { mockClient } from './mock-client';
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import type { KbdbClient } from '../src/lib/kbdb-client';
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async function seed(c: KbdbClient) {
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// A — B — C，D 孤立連 A
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await createTriplet(c, { subject: 'A', predicate: 'r', object: 'B' });
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await createTriplet(c, { subject: 'B', predicate: 'r', object: 'C' });
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await createTriplet(c, { subject: 'A', predicate: 'r', object: 'D' });
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}
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describe('graph-nodes', () => {
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it('listNodes 統計 edge_count', async () => {
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const c = mockClient();
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await seed(c);
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const nodes = await listNodes(c, {});
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const a = nodes.find((n) => n.node === 'A');
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expect(a?.edge_count).toBe(2);
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});
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it('getNeighbors 收鄰居', async () => {
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const c = mockClient();
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await seed(c);
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const neighbors = await getNeighbors(c, 'A');
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expect(neighbors.sort()).toEqual(['B', 'D']);
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});
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it('getNodeEdges 取邊', async () => {
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const c = mockClient();
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await seed(c);
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const edges = await getNodeEdges(c, 'B');
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expect(edges.length).toBe(2);
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});
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});
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describe('graph-path', () => {
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it('A→C 最短路經過 B', async () => {
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const c = mockClient();
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await seed(c);
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const res = await findShortestPath(c, 'A', 'C');
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expect(res.path).toEqual(['A', 'B', 'C']);
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});
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});
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